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Exercise 9.6
Something like a Wien bridge oscillator
a)
An answer:
H
loop
(
jω
)
=
A
⋅
H
1
(
jω
)
⋅
H
2
(
jω
)
H
1
(
jω
)
=
1
∕
jω
C
1
R
1
+
1
∕
jω
C
1
=
1
1
+
jω
C
1
R
1
H
2
(
jω
)
=
R
2
R
2
+
1
∕
jω
C
1
=
jω
R
2
C
2
1
+
jω
C
2
R
2
H
loop
(
jω
)
=
A
⋅
1
1
+
jω
C
1
R
1
⋅
jω
R
2
C
2
1
+
jω
C
2
R
2
=
A
⋅
jω
R
2
C
2
1
+
jω
R
2
C
2
+
jω
R
1
C
1
−
ω
2
R
1
C
1
R
2
C
2
=
A
⋅
1
1
jω
R
2
C
2
+
1
+
R
1
C
1
R
2
C
2
+
jω
R
1
C
1
yielding:
ω
osc
=
1
R
1
C
1
R
2
C
2
b)
An answer:
H
loop
(
ω
osc
)
=
A
⋅
1
1
+
R
1
C
1
R
2
C
2
A
=
1
+
R
1
C
1
R
2
C
2
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