Exercise 3.10 Bias issues within an antenna amplifier

a)


An answer:
With the assumptions described in the hint (ignore base current of the proceeding stage) a derivation could be as shown below. Note that the supply voltage in this particular circuit is denoted as V B1...

IC2 = βfe βfe + 1IE2 IE2 = V E2 RE2 V E2 = V B2 V BE2 V B2 = V B1 RB21 RB21 + RB22 IB2 RB21RB22 RB21 + RB22 IB2 = IC2 βfe IC2 = βfe βfe + 1 V B1 RB21 RB21+RB22 IC2 βfe RB21RB22 RB21+RB22 V BE2 RE2 = βfe βfe + 1 V B1 RB21 RB21+RB22 V BE2 RE2 + 1 βfe+1 RB21RB22 RB21+RB22

Also V E2 = βfe+1 βfe IC2RE2

For the derivation of IC3:

IC3 = βfe βfe + 1IE3 IE3 = V E3 RE3 V E3 = V E2 V BE3 IC3 = βfe βfe + 1 V E2 V BE3 RE3

Where you may substitute the earlier found relation for V E2.

b)


An answer:

IC2 2.05mA IC3 1.6mA

c)

An answer:
This relates to small signal properties, in this case to voltage gain of the stages. See therefore chapters 4 and 5.

R9 is decoupled because any (signal induced) change in the base voltage appears in full across V BE of Q3 which results in maximum sensitivity. For biasing purposes, the circuit should be insensitive to changes: at DC we want to have a relatively high ohmic emitter series resistance.

If R6 would be similarly decoupled there would be no signal present at the base of Q3. Then the voltage gain of the stage with Q3 would be zero.