Exercise 6.11 Non linear feedback around an opamp configuration

a)


An answer:

vout = v−− vBE v+ = v− = 0 vBE = kT q ln ⁡ ic IC0 vout = −kT q ln ⁡ vin IC0R

b)


An answer:

pict

gBJT = ∂iC ∂vBE = q kTIC0e qV BEkT = q kTIC

rout,circuit = vo io io = vo R1 + rbjt + vo + A ⋅ vo R1 R1+rbjt rout = vo( 1 R1 + rbjt + 1 + A R1 R1+rbjt rout ) rout,circuit = (R1 + rbjt)∕∕ rout 1 + A R1 R1+rbjt with  rbjt = kT q 1 IC = kT q R V IN