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Exercise 6.11
Non linear feedback around an opamp configuration
a)
An answer:
v
o
u
t
=
v
−
−
v
B
E
v
+
=
v
−
=
0
v
B
E
=
k
T
q
ln
i
c
I
C
0
v
o
u
t
=
−
k
T
q
ln
v
i
n
I
C
0
R
b)
An answer:
g
B
J
T
=
∂
i
C
∂
v
B
E
=
q
k
T
I
C
0
e
q
V
B
E
k
T
=
q
k
T
I
C
r
o
u
t
,
c
i
r
c
u
i
t
=
v
o
i
o
i
o
=
v
o
R
1
+
r
b
j
t
+
v
o
+
A
⋅
v
o
R
1
R
1
+
r
b
j
t
r
o
u
t
=
v
o
(
1
R
1
+
r
b
j
t
+
1
+
A
R
1
R
1
+
r
b
j
t
r
o
u
t
)
r
o
u
t
,
c
i
r
c
u
i
t
=
(
R
1
+
r
b
j
t
)
∕
∕
r
o
u
t
1
+
A
R
1
R
1
+
r
b
j
t
with
r
b
j
t
=
k
T
q
1
I
C
=
k
T
q
R
V
I
N
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