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Exercise 6.9
Opamp configuration with series impedance in the loop
a)
An answer:
z
o
=
v
o
i
o
i
o
=
v
o
−
A
(
v
+
−
v
−
)
z
x
=
v
−
(
1
+
A
)
−
A
v
+
z
x
v
+
=
v
i
≡
0
i
o
=
v
o
(
1
+
A
)
z
x
z
o
=
R
2
1
+
A
⋅
1
1
+
jω
R
2
C
1
b)
An answer:
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